Question posted 2009 · +5 upvotes
Why doesn’t the average of the score of an employee of each month, when summed, equal the average of the employees score (ever)?
Average
SELECT Avg(r.score) AS rawScore
FROM (ET INNER JOIN Employee AS e ON ET.employeeId = e.id) INNER JOIN (Employee AS a INNER JOIN Review AS r ON a.id = r.employeeId) ON ET.id = r.ETId
WHERE (((e.id)=@employeeId))
Returns 80.737
Average By Month
SELECT Avg(r.score) AS rawScore, Format(submitDate, 'mmm yy') AS MonthText, month(r.submitDate) as mm, year(submitDate) as yy
FROM (ET INNER JOIN Employee AS e ON ET.employeeId = e.id) INNER JOIN (Employee AS a INNER JOIN Review AS r ON a.id = r.employeeId) ON ET.id = r.ETId
WHERE (((e.id)=@employeeId))
GROUP BY month(r.submitDate), year(submitDate), Format(submitDate, 'mmm yy')
ORDER BY year(submitDate) DESC, month(r.submitDate) DESC
Returns
Average Score : Month
81.000 : Oct 09
80.375 : Sep 09
82.700 : Aug 09
83.100 : Jul 09
75.625 : Jun 09
I know 80.737 is correct because I have tallied up the records by hand and done the average. But the average of this table (at 3 decimal places), is 80.56 which is too far off. Does group by mess with the rounding at each step?
Accepted answer +7 upvotes
An average of average values will not return the same result as a single average over all values, unless all the groups averaged have the same number of items.
If there are different numbers of employees rawScore each month it will be skewing your results.
Consider this example: if we calculate the average of the numbers 1 through 10 the average is 5.5.
Calculating the average of the numbers from 1 through 5 the average is 3, and of 6 through 10 is 8. Both groups have 5 items so the average of 3 and 8 = 5.5.
However, if you take the first average as 1 and 2 = 1.5, and the second average as 3 through 10 = 6.5, then average 1.5 and 6.5 gives 4. This is skewed because the first group has 2 items, and the second has 8.
In addition to this will be the cumulative effects of rounding that Robert Harvey noted.
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